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A gradient function is given by dy/dx= 10e^(2x) -5 . When x = 0, y = 8. Find the value of y when x = 1. Help?
I keep getting 34.9, which is apparently incorrect.
3 Answers
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- 5 years agoFavorite Answer
dy = 10 * e^(2x) * dx - 5 * dx
y = (10/2) * e^(2x) - 5x + C
y = 5 * e^(2x) - 5x + C
y = 8 when x = 0
8 = 5 * e^(0) - 5 * 0 + C
8 = 5 * 1 - 0 + C
8 = 5 + C
3 = C
y = 5 * e^(2x) - 5x + 3
y = 5 * e^(2 * 1) - 5 * 1 + 3
y = 5 * e^(2) - 5 + 3
y = 5 * e^(2) - 2
I'm getting the same thing.
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