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? asked in Science & MathematicsChemistry · 5 years ago

Heat Curves! Chemistry help!?

Calculate the energy required to heat 10.0 g of solid ice at 0.0˚C to liquid water at 80.0˚C. It may help to draw a heating curve and to use some of the following values:

Cs,ice : 2.09 J/g˚C

Cs,water : 4.184 J/g˚C

Cs,steam : 2.03 J/g˚C

∆Hfus, water : 334 J/g

∆Hvap, water : 2260 J/g

1 Answer

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  • Roger the Mole
    Lv 7
    5 years ago

    (334 J/g) x (10.0 g) = 3340 J to melt the ice

    (4.184 J/g˚C) x (10.0 g) x (80.0 - 0.0)˚C = 3347 J to warm the melted ice to 80.0˚C

    3340 J + 3347 J = 6687 J total

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