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Need help with this simple calculus problem?
At t = 0, a train approaching a station begins decelerating from a speed of 80 mi/hr according to the acceleration function a(t) = -1280(1+8t)^-3 mi/hr^2, where t >= 0. How far does the train travel between t = 0 and t = 0.2?
Between t = 0.2 and t = 0.5?
Between t = 0 and t = 0.2 the train travels ??? mi.
1 Answer
- MechEng2030Lv 74 years agoFavorite Answer
v(t) = 80(1 + 8t)^(-2)
s(t) = -10/(1 + 8t)
Between t= 0 and t = 0.2 => s(0.2) - s(0)
= -50/13 + 10
= 80/13 mi.
Between t = 0 and t = 0.5 => s(0.5) - s(0)
= -2 + 10
= 8 mi
