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Trig problem?
The point P(-4,-2) is on the terminal side of angle theta in standard position with 0< or equal to theta < 360
Use definitions of trigonometric functions of any angle to find cos sin and tan
3 Answers
- ?Lv 74 years ago
Opposite side = -2, Adjacent side = -4, and Hypotenuse = √(4²+2²) = √20 = 2√5
sinθ = Opposite/Hypotenuse = -2/(2√5) = -1/√5 or if you prefer -√5 / 5
cosθ = Adjacent/Hypotenuse = -4/(2√5) = -2/√5 or if you prefer -2√5 / 5
tanθ = Opposite/Adjacent = -2/-4 = 1/2
- DWReadLv 74 years ago
P is in quadrant III
sinθ = (-2)/√(4²+2²) = -2/(3√2) = -2√2/6
cosθ = (-4)/√(4²+2²) = -4/(3√2) = -4√2/6
tanθ = sinθ/cosθ
- Ahmed AbaLv 64 years ago
(-4)^2+(-2)^2=h^2
16+4=20 =h^2,h=sqr20=sqr(4(5)=2sqr5
sin(x)=-2/2sqr5=-1/sqr5
cosx=-4/2sqr5=-2/sqr5
tanx=-4/-2=2