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? asked in Science & MathematicsMathematics · 4 years ago

Trig problem?

The point P(-4,-2) is on the terminal side of angle theta in standard position with 0< or equal to theta < 360

Use definitions of trigonometric functions of any angle to find cos sin and tan

3 Answers

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  • ?
    Lv 7
    4 years ago

    Opposite side = -2, Adjacent side = -4, and Hypotenuse = √(4²+2²) = √20 = 2√5

    sinθ = Opposite/Hypotenuse = -2/(2√5) = -1/√5 or if you prefer -√5 / 5

    cosθ = Adjacent/Hypotenuse = -4/(2√5) = -2/√5 or if you prefer -2√5 / 5

    tanθ = Opposite/Adjacent = -2/-4 = 1/2

  • DWRead
    Lv 7
    4 years ago

    P is in quadrant III

    sinθ = (-2)/√(4²+2²) = -2/(3√2) = -2√2/6

    cosθ = (-4)/√(4²+2²) = -4/(3√2) = -4√2/6

    tanθ = sinθ/cosθ

  • 4 years ago

    (-4)^2+(-2)^2=h^2

    16+4=20 =h^2,h=sqr20=sqr(4(5)=2sqr5

    sin(x)=-2/2sqr5=-1/sqr5

    cosx=-4/2sqr5=-2/sqr5

    tanx=-4/-2=2

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