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help on this problem?
find the area of the region enclosed between two curves.
y = 4-x^2 and y = x + 2
2 Answers
- Ahmed AbaLv 64 years agoFavorite Answer
find points of intercectio x+2=4-x^2
x^2+x +2-4=0
x^2+x-2=0,,,(x+2)(x-1)=0,,,then x=-2,x=1
int(4-x^2)-(x+2) dx from -2 to 1
int(4-x^2-x-2)dx=int(-x^2-x+2)dx
=(-x^3/3 -x^2/2+2x) substitute 1 then -2
(-1/3 -1/2+2)-((-(-2)^3/3) -(-2)^2/2+2(-2) )
(-2/6-3/6+12/6)-(-8)/3-(4/2)-4)
(7/6)-((-16/6 ) -12/6)+24/6)
(7/6)-(-28+24)/6=7/6)-(-4/6)
11/6
