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Trig Co-function Problem?
Suppose that cos(pi/2-theta)=x/3 where 0<theta<pi/2. express the quantity (cot theta + theta) as a function of x
Can someone help me solve this problem.
Update:
theta is an acute angle
1 Answer
Relevance
- DWReadLv 74 years ago
What does "(cot theta + theta)" mean?
cos(π/2 - θ) = x/3
cos(π/2)cosθ + sin(π/2)sinθ = x/3
0·cosθ + 1·sinθ = x/3
sinθ = x/3
cos²θ = 1-sin²θ = (9-x²)/9
cosθ = √(9-x²)/3
cotθ = cosθ/sinθ = √(9-x²)/x
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