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A asked in Ciencias y matemáticasMatemáticas · 4 years ago

¿Calcular el numero de soluciones de la ecuacion 5*log(x)-x=0. (log= logaritmo neperiano).?

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  • torquemada
    Lv 7
    4 years ago
    Favorite Answer

    ******************

    5*ln(x) - x = 0

    El polinomio en x no se puede factorizar por tanto

    no se puede hallar el valor de x en forma algebraica

    ln(x) = x/5

    x = e^(x/5)

    x^5 = e^x

    5 ln(x) = x

    5 ln(x) - x = 0

    por medio de su gráfica obtenemos los valores

    x1 ~ 1.3

    x2 ~ 12.7

    https://www.wolframalpha.com/input/?i=5*log(x)+-+x...

    ...

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