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Capacitor Design?
You must design a capacitor capable of storing 4.10 × 10-7 C of charge, but you only have a 170- V power supply and two metal plates of area 0.405 m2 each. What is the largest value the plate separation can be so that you can accomplish the task?
1 Answer
- az_lenderLv 74 years ago
Q = CV and C = A(eps-nought)/d,
so the limit on "d" is
A(eps-nought)/C = A(eps-nought)V/Q.
Here epsilon-nought is 8.854 x 10^(-12) C/(Vm)
and A = 0.405 m^2, V = 170V, Q = 4.1x10^7 C.
The "d" is going to come out in meters,
looks like it'll be less than a femtometer (!),
but use a calculator.