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Integrate (4/5)/(x+3) + (11/5)/(x - 2) dx?
I get the obvious (4/5)ln(x + 3) + (11/5)ln(x - 2) + c, however Wolfram Alpha is telling me the answer is (4/5)ln(x + 3) + (11/5)ln(2 - x) + c
Can anyone explain why we have ln(2 - x) instead of ln(x - 2)?
1 Answer
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- 4 years ago
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