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MATH HELP????????????
1. How much pure acid should be mixed with
5gallons ofa20 %acid solution in order to geta nbsp 50 %acid solution??
2 Answers
- hayharbrLv 74 years ago
Alternate solution: % times amount of each part added together = % times amount of final mix
g = gallons of pure (100%) acid added
20 • 5 + 100 • g = 50(5 + g)
100 + 100g = 250 + 50g
-100 -50g .... -100 - 50g
-------------------------------------
50g = 150
g = 3
- ?Lv 74 years ago
20% of 5 is 1, so we start with 1 gal of acid
to 5 gal solution. That's a ratio of 1 / 5.
Suppose we add x gal acid. Then we have
1 + x gal acid to 5 + x gal solution.
Since 50% = 1/2, we have (1 + x) / (5 + x) = 1/2
Solving, x = 3 gal acid.
