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SkyEscape
SkyEscape asked in Science & MathematicsMathematics · 4 years ago

pls help diferential equations?

Suppose that s(t) = 1 + 5t - 2t^2 is the position function of a particle, where s is in meters and t is in seconds. Find the particle’s instantaneous velocity at time t=1.5 s.

4 Answers

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  • Como
    Lv 7
    4 years ago
    Favorite Answer

    s ` (t) = 5 - 4 t

    s ` (1.5) = 5 - 6 = - 1

  • Keith A
    Lv 6
    4 years ago

    s' (t) = 5 - 4t

    When t = 1.5, s'(t) = 5 - 6 = -1

    The velocity after 1.5 sec is 1 m/s backwards.

  • moondog
    Lv 6
    4 years ago

    ds/st(1.5)=5-4t now do the math, you realize why the derivative of your speed or velocity equation is the 'instanteous' velocity at time t, right?

  • stanschim
    Lv 7
    4 years ago

    s'(t) = 5 -4t

    s'(1.5) = 5 - 4(1.5) = 5 - 6 = -1 meters / sec

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