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TheUgly
TheUgly asked in Science & MathematicsMathematics · 4 years ago

OMG PLEASE HELP ME!! ITS QUICK! CALC QUESTION?

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3 Answers

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  • Sqdancefan
    Lv 7
    4 years ago

    The change in position is equal to the area under the curve

    .. (-5 cm/s)*(4 s) = -20 cm

    That is, 20 cm to the left.

  • Ash
    Lv 7
    4 years ago

    since the particle's position is constant at -5 cm between t=0 and t-4 sec, the change in position is 0 cm

  • ted s
    Lv 7
    4 years ago

    all that I can see is that the velocity is constant....but I know it is > - 5 but it could also be > 0 ......if > 0 then moving right , if 0 then particle is at rest , if < 0 then moving left ...

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