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need help in this mixture problem ...?
How many kilograms of sugar costing 9 rupees per kg must be mixed with 27 kg of sugar costing 7 rupees per kg so that there must be a gain of 10% by selling the mixture at 9.24 rupees per kg ??
answer - 63 kg
1 Answer
- ?Lv 74 years agoFavorite Answer
If there's a gain of 10% selling at 9.24 rs/kg,
then 9.24 rs/kg must be 110% of the cost.
so the cost of the mixture must be
9.24/110% = 9.24 / 1.1 = 8.40 rs/kg
Let x be the amount of the sugar costing 9 rs/kg to be added.
Then its cost is 9x.
The cost of the other sugar is
(27 kg) (7 rs/kg) = 189 rs
The amount of the mixture is, of course, x+27 kg
and its cost must be
(x+27 kg) (8.40 rs/kg)
in order to meet the objective.
So we just need to solve this equation:
9x + 189 = (x + 27) 8.40
9x + 189 = 8.40x + 226.8
9x - 8.40x = 226.8 - 189
0.60x = 37.8
x = 37.8 / 0.60 = 63 kg
