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What's the perimeter of this please?

A square is attached below a 30-60-90 angle, the square's size is 6cm and it is the same size of the angle adjacent to the right angle of the triangle, please find the parameter

Update:

I mean the line adjacent to the right angle is also 6 cm

Update 2:

https://imgur.com/a/idE8h here's the link to the pic, sorry I'm bad at explaining

Update 3:

Thanks for the answers@!

4 Answers

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  • 4 years ago
    Favorite Answer

    Can you use the same English that was used in the question?

    Depending on where the angles are located: Check the image

    6/h = cos60

    h = 12

    o = √(12² - 6²) = 6√3

    Perimeter = 3(6) + 6√3 + 12 = 30 + 6√3

    6/h = cos(30°)

    h = 4√3

    o = √((4√3)² - 6²) = 2√3

    Perimeter = 3(6) + 2√3 + 4√3 = 18 + 6√3

    Attachment image
  • ?
    Lv 7
    4 years ago

    In a 30°-60°-90° triangle

    the sides are in the ratio 1 : 2 : √3.

    P = 24√3 cm = 41.569219381653056 cm

  • 4 years ago

    Updated it, sorry, I'm really bad at explaining

  • 4 years ago

    Your description is ambiguous. I'm going to assume that the longer leg is vertical and that the square's side is the same length as the short leg of the triangle. Then the perimeter of the figure consists of the three sides of the square, plus the hypotenuse of the triangle, plus the longer leg of the triangle. Their lengths are

    6 + 6 + 6 + 12 + 3*sqrt(3) = 30 + 5.196 = 35.2 cm.

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