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URGENT HELP!! θ is an acute angle in a right triangle. Find the values of the six trigonometric functions given the following:?
(1 pt) Assume that θ is an acute angle in a right triangle. Find the values of the six triginometric functions given the following:
cos(θ)=25/28.
See attached photo
please show the work and how its done please thanks soo much!!!!!
2 Answers
- ?Lv 73 years ago
cos(θ)=25/28
adjacent = 25
hypotenuse = 28
opposite = √159 (by Pythagoras)
sin θ = (√159)/28, csc θ = 28/√159
sec θ = 28/25
tan θ = (√159)/25, cot θ = 25/√159
- L. E. GantLv 73 years ago
Well, sec = 1/cos. csc = 1/sin and cot = 1/tan
and tan = sin/cos...
So, you have two ways of finding sin...
cos = adjacent/hyp
sin = opp /hyp
opp^2 + adj^2 = hyp ^2
opp = √(28^2 - 25^2)
so, now put in the values and do the arithmetic...
or,,,
if you know trig identities
sin = √(1 - cos^2) etc.
