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jorden
jorden asked in Science & MathematicsEngineering · 3 years ago

an electrical motor provides power to a winding machine. the input power ti the motor is 4 kw and overall efficiency is 75. calculate?

Update:

a) the power output of the machine b)the velocity at which it can raise a 509.7 kg load vertically upwards

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  • billrussell42
    Lv 7
    3 years ago

    4 kW x 0.75 = 3 kW

    509.7 kg x 9.8 m/s² = 4995 N weight

    to raise that weight 1 meter requires 4995 J of energy

    how fast can it do that?

    3000 watts is 3000 J/s

    4995 J / 3000 J/s = 1.665 sec

    since it raised the weight 1 m in 1.665 sec, the velocity is 1/1.665 m/s = 0.601 m/s

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