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Austin Riley
Austin Riley asked in Science & MathematicsMathematics · 3 years ago

HELP!! Find all solutions of the equation 3sin2x−7sinx+2=0 in the interval [0,2π).?

Can you show me the work on how this is done please!??

I am lost and keep getting it wrong.

(see attached photo for the question)

thanks!!!

Attachment image

2 Answers

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  • Como
    Lv 7
    3 years ago

    I suspect that should be shown as :-

    3 sin²x - 7 sin x + 2 = 0

    [ 3 sin x - 1 ] [ sin x - 2 ] = 0

    sin x = 1/3

    x = 0•34 radians , 2•8 radians

  • DWRead
    Lv 7
    3 years ago

    You need to use ^ to indicate an exponent, e.g., 3sin^2x = 3sin²x

    3sin²x - 7sinx + 2 = 0

    quadratic formula

    sin(x) = [7 ± √(7² – 4·3·2)] / [2·3]

     = [7 ± √25] / 6

     = [7 ± 5] /6

     = 2, ⅓

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