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Base voltage divider question?

What is this formula R1 / R2 = ~1 / 1.17?

Why did he multiply 75kΩ with 2.17 / 1.17 to get R1?

https://youtu.be/WZD9RZoMhVE?t=10m49s

Update:

Where did you get the 6.9V value?

Update 2:

Oh 7.5V - 0.6V

Update 3:

Oh 15V - 8.1V

Attachment image

1 Answer

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  • 3 years ago
    Favorite Answer

    That is a strange way of calculating bias. Not one I would ever use.

    ratio of voltage across those two resistors is 6.9v/8.1v according to the schematic.

    and that is 1/1/17

    ratio of R1+R2 to R2 is (1+1.17)/1.17 = 2.17/1.17

    skip all that, here is how you calculate R1 and R2.

    Take HFE of transistor and divide Ic by that to get Ib. In this case 1000µa/100 = 10µA.

    You want the bias current thru R1,2 to be higher than that, say 10 x, 100 µA.

    R2 = 8.1/100µA = 81kΩ

    R1 = 6.9/100µA = 69kΩ

    those values will work as well as the ones from that utube video.

    he used a different ratio, looks like 5x, 50µA, which gives you 160k and 140k, essentially what he has.

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