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Need help in this percentage problem ?

Update:

according to a survey 41% , 35% and 60% of people in town like Ranbir , Ajay and John respectively . 27% of people like exactly two of the three men . 3% of people like none . it is also known that 16% of people like ranbir and john and 14% of people like Ajay and John , then what percentage of people like only Ajay ??

Update 2:

answer is 12% ...please help

1 Answer

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  • ?
    Lv 7
    3 years ago
    Favorite Answer

    I'm going to make up some variables with one, two, or 3-letter names

    instead of the usual one-letter names, to keep track better.

    So let

    AJR = the percentage of people who like all three.

    AJ = the percentage of people who like Ajay and John but not Ranbir.

    AR = the percentage of people who like Ajay and Ranbir but not John.

    JR = the percentage of people who like John and Ranbir but not Ajay.

    A = the percentage of people who like only Ajay.

    J = the percentage of people who like only John.

    R = the percentage of people who like only Ranbir.

    Now we can write equations for the given information:

    {1} AJR + AR + JR + R = 41

    {2} AJR + AJ + AR + A = 35

    {3} AJR + AJ + JR + J = 60

    {4} AJ + AR + JR = 27

    {5} AJR + AJ + AR + JR + A + J + R = 97

    {6} AJR + JR = 16

    {7} AJR + AJ = 14

    That's the given information. Now we need to solve for A.

    {8} 3(AJR) + 2(AJ + AR + JR) + A + J + R = 136 [adding {1}, {2}, and {3}]

    {9} 3(AJR) + AJ + AR + JR + A + J + R = 109 [subtracting {4} from {8}]

    {10} 2(AJR) = 12 [subtracting {5} from {9}]

    {11} AJR = 6 [dividing each side of {10} by 2]

    {12} JR = 10 [subtracting {11} from {6}]

    {13} AJ = 8 [subtracting {11} from {7}]

    {14} AR = 9 [subtracting BOTH {12} and {13} from {4}]

    {15} 6 + 8 + 9 + A = 35 [substituting for variables in {2}, using {11}, {13}, and {14}]

    {16} A = 12 [solving {15} for A]

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