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Physics help!!?
A block of mass 5kg sits on an inclined plane, which is slowly being raised. The block remains motionless until the angle the plane makes with the horizontal is 22°. At this angle, the block begins to slide down the plane. What is the coefficient of static friction between the plane and the block?
1 Answer
- Andrew SmithLv 72 years ago
The normal reaction is mg cos( theta)
The force along the plane is mg sin(theta)
as the coefficient is the force along the plane/ normal reaction at the point of just sliding
coefficient = mg sin ( theta) / ( mg cos(theta) ) = tan(theta) = tan(22 deg)
