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calculate internal energy given two temperature ?
calculate internal energy when 1 mole of H2O goes from 25 degree C at 1 atm pressure goes to 30 degree C at 1 atm pressure . . Densities of water are 0.997 g/cm^3 at 0 degree C and 0.995 g/cm^3 at 100 degree C
please help
1 Answer
- billrussell42Lv 72 years agoFavorite Answer
1 mole of water is 2•1.008 + 15.999 = 18.015 g
CHANGE in energy = 4.186 J/gC x 18.015 g x 5ºC = 377 J
specific heat of water is 4.186 kJ/kgC = 4.186 J/gC
= 1 calorie/gC = 5.375 J/mol·K = 1 Btu/lb-F