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Section 2.1 Problem 2 The slope of the tangent line to the graph of f(x) at x=13 is m=?
2 Answers
- Anonymous2 years ago
I'm confused to what the answers are
- 2 years ago
(f(13 + h) - f(13)) / h =>
(sqrt(13 + h + 3) - sqrt(13 + 3)) / h =>
(sqrt(16 + h) - sqrt(16)) / h =>
(sqrt(16 + h) - 4) / h =>
(sqrt(16 + h) - 4) * (sqrt(16 + h) + 4) / (h * (sqrt(16 + h) + 4)) =>
(16 + h - 16) / (h * (sqrt(16 + h) + 4)) =>
h / (h * (4 + sqrt(16 + h))) =>
1 / (4 + sqrt(16 + h))
h = 0.1
1 / (4 + sqrt(16.1))
h = 0.01
1 / (4 + sqrt(16.01))
And so on
Let h = 0
1 / (4 + sqrt(16 + 0)) =>
1 / (4 + sqrt(16)) =>
1 / (4 + 4) =>
1/8
y - 4 = (1/8) * (x - 13)
Solve for y