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Let f(x)=21+x2. The tangent line to the curve at the point (2,0.40000) can be written in the form y=mx+b where m is: and where b is:?
Update:
#12
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- rotchmLv 72 years ago
The slope of f(x) at point x is f '(x). Evaluate this at x = 2 to get your slope m.
Now, this point also belongs to to your sought line. That is, 0.4 = m*2 + b. Since u found m, just solve for b.
Done!
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