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3 Answers
- ?Lv 62 years ago
ln (uv²)⁹
= 9 ln (uv²) {from ln aⁿ = n ln (a)}
= 9 [ln u + ln v²] {from ln (ab) = ln a + ln b}
= 9 [ln u + 2 ln v]
= 9 ln u + 18 ln v -- (*)
By comparing A ln u + B ln v with what we have in (*), we conclude that A = 9 & B = 18.
Source(s): From the Laws of Natural Logarithm. - ?Lv 72 years ago
ln (uv²)⁹ = 9 ln (uv²)
.............= 9 [ln u + ln v²]
.............= 9 [ln u + 2 ln v]
.............= 9 ln u + 18 ln v
.............= A ln u + B ln v
⇒
A = 9, B = 18..................ANS
- stanschimLv 72 years ago
I will assume the the squared operation only applies to the variable, v.
ln(uv^2)^9 = 9ln(uv^2) = 9[ln(u) + 2ln(v)] = 9ln(u) + 18ln(v). A = 9 and B = 18.
