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physics help?
A friend throws a baseball horizontally. He releases it at a height of 2.0 m and it lands 21 m from his front foot, which is directly below the point at which he released the baseball.
(a) How long was it in the air?
(b) How fast did he throw it?
2 Answers
- oubaasLv 72 years agoFavorite Answer
(a) How long (t) was it in the air?
2h = g*t^2
t = √2h/g = √2*2/9.806 = 0.6387 sec
(b) How fast (V) did he throw it?
V = d/t = 21/0.6387 = 32.880 m/sec
- electron1Lv 72 years ago
Let’s use the following equation to determine the time to fall 2.0 meters.
d= vi * t + ½ * g * t^2
Let’s use the following equation to determine the time to fall 2.0 meters/
2.0 = ½ * 9.8 * t^2
t = √(4 ÷ 9.8)
The time is approximately 0..64 second. Let’s use the following equation to determine its horizontal velocity.
v = d ÷ t
v = 21 ÷ √(4 ÷ 9.8)
This is approximately 32 m/s.
