If y=5/x what happens to y as x increases?

y decreases as x increases

If the denominator of a fraction increases, the value of the the fraction, in this case y, decreases. The denominator can never reach +infinity, therefore, as the value of x increases, the value of y approaches, but never reaches, zero.

Type this into Google or wolfram alpha to see for yourself. You should learn how to draw 5\x type curves.

1. "As X increases y decreases" - as X goes to infinity y tends to zero, "5 divided by something very big equals something very small"

2. "As X decreases y increases" - as X tends to zero y tends to infinity, "5 divided by something very very very small equals something very big"

As x increases (i.e. approaches infinity) in the equation y = 5/x, then y approaches 0. This is done via the concept of limit in calculus, meaning

Lim. x → ∞: y

= Lim. x → ∞: 5/x

= 5 Lim. x → ∞: (1/x)

= 5 (0)

= 0 ...Ans.

Hence as x → ∞, y → 0 in y = 5/x.

y would decrease until it reaches a number so close to 0 that it becomes 0

X = 8=======D

As x -> oo , y --> 0

I am being difficult now, but consider this test.

When x = -1, y = -5.

When x = 1, y = 5.

There you have it. When x increased, y also increased. Be careful with discontinuities.

It changes or course.

Assuming both are positive, y and x are inversely proportional, so as x increases, y decreases (and vice versa).

Try a few values and see if this makes sense:

x = 1 --> y = 5

x = 2 --> y = 2.5

x = 3 --> y = 1.666...

x = 4 --> y = 1.25

x = 5 --> y = 1

x = 6 --> y = 0.8333...

etc.

If it helps, imagine x was the number of people sharing 5 pizzas. As you increase the number of people, the amount of pizza each person receives gets smaller and smaller.