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concave lens has a focal length of 34 cm.Find image distance+ magnification that results when an object is placed 23 cm in front of lens?
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- Anonymous2 years ago
s1 = object distance
s2 = image distance
1/s1 + 1/s2 + 1/f = 0
1/s2 = - 1/s1 - 1/f
s2 = - (s1 f) / (s1 + f)
s2 = - (23*34) / (23 + 34) = - 13.72 cm (virtual image)
magnification is
M = - s2 / s1 = 13.72 / 23 = 0.6
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