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The number of radioactive nuclei in a particular sample decreases over a period of 14 d to one-sixteenth the original number?
Update:
What is the half-life of these nuclei?
Express your answer using two significant figures.
2 Answers
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- JimLv 72 years ago
1/16 = 1/2^4
Half-life is a very simple formula!
A = A₀ (½)^(t/h)
Where
A = remaining amount
A₀ = original amount
t = the time lapsed (in same units as h)
h = time of half life
1/2^4 = (½)^(14/h)
4 = 14/h
h = 14/4 = 7/2
h = 3.5 day
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Nice that it was even ike this, typically we must solve using logs
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