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Electrostatic physics question?
How far apart must two point charges of 55.0 nC (typical of static electricity) be to have a force of 3.40 N between them?
mm
1 Answer
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- Anonymous2 years agoFavorite Answer
Electrostatic force is
F = k q^2 / r^2
then
r = q (k / F)^1/2
where
k = 9x10^9 Nm^2/C^2 [Coulomb constant]
then
r = 5.5x10^-8*(9x10^9 / 3.4)^1/2 = 2.83 mm
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