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Label the asymptotes. (𝑦−3)^2/1 - (x+2)^2/4 = 1?
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- TomVLv 72 years agoFavorite Answer
Interpreted in accord with the PEMDAS rules:
(y-3)^2/1 - (x+2)^2/4 = 1
is a hyperbola whose asymptotes can be found as:
(y-3)² - (x+2)²/4 = 0
[(y-3) + (x+2)/2][(y-3) - (x+2)/2] = 0
y = 2 - x/2
y = 4 + x/2
The slant asymptotes of the hyperbola are the lines:
y = 2 - x/2
y = 4 + x/2
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