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Christopher
Lv 5
Christopher asked in Science & MathematicsMathematics · 2 years ago

Limit Math?

lim (x→∞) [√(16x²+5x-x)/2x]

3 Answers

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  • Captain Matticus, LandPiratesInc
    Lv 7
    2 years ago
    Favorite Answer

    Is that supposed to be:

    sqrt(16x^2 + 5x) - x?

    (sqrt(16x^2 + 5x) - x) / (2x) =>

    (sqrt(x^2 * (16 + 5/x)) - x) / (2x) =>

    (x * sqrt(16 + 5/x) - x) / (2x) =>

    x * (sqrt(16 + 5/x) - 1) / (2x) =>

    (sqrt(16 + 5/x) - 1) / 2

    x goes to infinity

    (sqrt(16 + 5/inf) - 1) / 2 =>

    (sqrt(16 + 0) - 1) / 2 =>

    (sqrt(16) - 1) / 2 =>

    (4 - 1) / 2 =>

    3/2

  • ted s
    Lv 7
    2 years ago

    ( 2 ) ...factor out 4x from the top , cancel , take the limit

  • fatbubblebutt
    2 years ago

    Haha good one

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