How many protons are in 9.25 x 10-22 g of F?

start with the given .. convert to moles, then molecules, then atoms, then protons using the atomic number

(9.25 x 10-22 g) X (1mole/38g) X (6.022x10^23 molecules/mole) X (2atoms/molecule) X (9 protons/atom) = 263.86 protons round to 264 protons. <<<< mathematical answer .. but===

this question makes no sense .. if you 'cut off' the calculation at molecules

... (9.25 x 10-22 g) X (1mole/38g) X (6.022x10^23 molecules/mole) = 14.6588 molecules

.... and you can NOT have a fraction of a molecule.

9.25 x 10-22 ?? that is 92.5–22 = 70.5 g

Fluorine exists as F₂

F₂ is 38 g/mol

70.5 g / 38 g/mol = 1.86 mol

6.022e23 molecules/mole Avogadro constant

1.86 mol x 6.022e23 molecules/mole = 1.12e24 molecules

each F atom has 9 protons, so a F₂ molecule has 18 protons

1.12e24 molecules x 18 protons/molecule = 2.02e25 protons