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Matematica: come calcolare questo limite?
lim x->+inf (ln(x^3 +2 )) / (ln(5x^2 - 7)
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4^ scientifico: solo limiti notevoli
Grazie
2 Answers
- Anonymous2 years ago
lim x->+inf (ln(x^3 +2 )) / (ln(5x^2 - 7)
Trascurando nelle somme gli addendi che non vanno all'infinito
lim_x->+oo ln x^3 / ln (5x^2)
per le proprietà dei logaritmi questo equivale a
lim_x->+oo 3 ln x / [ ln 5 + 2 ln x ]
posto v = ln x
lim_v->+oo 3v/(2v + 5) =
= lim_v->+oo 3v/2v = 3/2
