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A rocket is launched off the top of a school. The flight of the rocket can be modelled by the quadratic equation, H(t) = -4t2+22t+5, where t represents the time in seconds, and H(t) represents the height of the rocket at time t. To the nearest whole metre, how high is the rocket after 1 second?
3 Answers
- llafferLv 72 years agoFavorite Answer
Solve for H(1):
H(t) = -4t² + 22t + 5
H(1) = -4(1)² + 22(1) + 5
H(1) = -4(1) + 22(1) + 5
H(1) = -4 + 22 + 5
H(1) = 23 m
