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Kevin
Kevin asked in Science & MathematicsMathematics · 2 years ago

I need Help with problem 3!!?

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2 Answers

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  • Steve A
    Lv 7
    2 years ago
    Favorite Answer

    For each class, multiply the median of the range by its frequency. Class 105-109 has median of 107. Its frequency is 2.

    107 * 2 = 214

    Do that for each class. Sum the results. Divide by the total frequency. That is the mean.

    The mode is what occurs most frequently. Two classes have the most with 8. List them both.

  • ?
    Lv 7
    2 years ago

    3!! = (3!)! = (6)! = 6! = 6*5*4*3*2*1 = [left for you].

    ;)

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