urgent physics question?

X = -82cos 30+175 = 104 km

Y = -82sin 30-45 = -41-45 = -86 km

displacement D = √104^2+86*2 = 135.0 km

average velocity = D/t = 135.0 / 3.2 = 42.2 km/h

heading angle = arctan Y/X = arctan -86/104 = -39.6° (E 39.6° S)

Add the easterly components to get the net easterly motion

Then add the northerly components to get the net Northerly motion.

Calculate the magnitude of the displacement by using Pythagoras' theorem.

Calculate the angle North of East from tan( theta ) = opposite / adjacent = North/ East

so theta = atan( north / east) where theta is the angle north of east

Finally velocity = displacement / time

Total displacement in East direction = -82cos30 + 0 + 175 = 104 km

Total displacement in South direction = 82sin30 + 45 + 0 = 86 km

Total displacement = √(104²+86²) = 135 km

Angle of displacement = tan⁻¹(86/104) = [E 39.59 S]

Average velocity = Total distance / Total time = (82+45+175)/3.2 = 302/3.2 = 94 km/hr