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Find the Confidence Level of Interval?

I'll omit the subscript so Z*α/2 becomes Z* for readability

I have the following confidence interval from a difference of proportions

[0.012, 0.148] = [0.08 - 0.0693Z*, 0.08 + 0.0693Z*]

What are the confidence/significant levels?

I believe you get Z* = 0.9809? Now I just need to find confidence (1 - α) and significance α using the right table. I'm just confused about which table, since we have the α/2 division of 2.

Update:

I get confidence is 67.3% with significance 0.327 o..o

1 Answer

Relevance
  • 1 year ago

      that is the right answer.

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