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Proving Quadrilateral Properties Help!?

Given: ABCD is a parallelogram and AC⊥ BD

Prove: AC bisects ∠BCD.

Update:

i've also added the congruent and parallel opposite sides. I'm stuck now

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1 Answer

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  • alex
    Lv 7
    1 year ago

    AC met BD at E --->△BCE≅△DCE by SAS (BE≅DE ,∠E = 90 degrees ,  CE≅CE)

    --->

    ∠BCE = ∠DCE

    or AC bisects ∠BCD

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