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Proving Quadrilateral Properties help!?

Given: ABCD is a parallelogram and 

AC 

bisects ∠BCD.

Prove:  AB ≅ BC

so far ive proven that △ABC≅△CDA by SSS and opposite sides are congruent. Idk where to go from here

 

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2 Answers

Relevance
  • 1 year ago

    idk, ask obama 

  • alex
    Lv 7
    1 year ago

    AC bisects ∠BCD.

    ∠BCA = ∠DCA= ∠BAC (alternate angles of AB//CD)

    ∠BCA = ∠BAC ---> triangle ABC is isosceles ---> AB=BC

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