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What is the equilibrium constant?
The equilibrium constant shown below has a Kc = 1.4 x 10^-4. If [A] = 0.24mol/L, what is [D]?
3A(g) + B(s) <--> C(s) + 2D(g)
1 Answer
- lenpol7Lv 711 months ago
kc = [D]^2 / [A]^3
'B' & 'C' are discounted because they are solids.
[D]^2 = [A]^3 Kc
[D]^2 = [0.24 mol L^-1]^3 X 1.4 x 10^-4
[D]^2 = 0.013824 mol^3 L^-3 X 1.4 X 10^-4
[D]^2 = 1.93536 x 10^-6
[D] = sqrt( 1.93536 x 10^-6 )
[D] = 1.3911 x 10^-3 mol/L