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What is the equilibrium constant?

The equilibrium constant shown below has a Kc = 1.4 x 10^-4. If [A] = 0.24mol/L, what is [D]?

3A(g) + B(s) <--> C(s) + 2D(g)

1 Answer

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  • 11 months ago

    kc = [D]^2 / [A]^3

    'B' & 'C' are discounted because they are solids.

    [D]^2 = [A]^3 Kc

    [D]^2 = [0.24 mol L^-1]^3 X 1.4 x 10^-4

    [D]^2 = 0.013824 mol^3 L^-3 X 1.4 X 10^-4

    [D]^2 = 1.93536 x 10^-6

    [D] = sqrt( 1.93536 x 10^-6 )

    [D] = 1.3911 x 10^-3 mol/L

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