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What is the inverse of the function given by f(x)=e^3x +1?
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- Jeff AaronLv 711 months ago
y = (e^3)x + 1
The inverse is:
x = (e^3)y + 1
x - 1 = (e^3)y
y = (x - 1) / (e^3)
y = (e^(-3))x - e^(-3)
Or did you mean:
y = e^(3x) + 1
The inverse is:
x = e^(3y) + 1
x - 1 = e^(3y)
3y = x - 1 + 2*i*pi*n, for any integer n
y = (x - 1 + 2*i*pi*n) / 3, for any integer n
If x and y are real numbers:
y = (x - 1) / 3, for any integer n
y = (1/3)x - (1/3)
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