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Can anyone calculate the circumference of earth at 21.458056 N parallel and the size of largest equilateral triangle fixing that circle?
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- 9 months agoFavorite Answer
The equatorial radius of the Earth is 6.3781 * 10^6 meters
6.3781 * 10^6 * cos(21.458056 degrees) = r[21.458056]
2 * pi * r[21.458056] = C[21.458056]
2 * pi * 6.3781 * 10^6 * cos(21.458056) =>
37.29702538131921006275934987106... * 10^6 meters =>
37.297 * 10^6 meters =>
3.7297 * 10^7 meters
I don't quite understand what the 2nd part of your question means.
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