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Is this a polynomial ( true or false ) ?
f(x) = x^3 + 2x^1/3
I would think its not a polynomial because its a binomial. I just want to verify
4 Answers
- ?Lv 75 months ago
First of all a binomial is a special polynomial just as a trinomial is a polynomial.
- ?Lv 65 months ago
Since we're talking about definitions, let's be precise, although this might seem petty and pedantic.
First of all, it's an equation, not an expression, so right off the bat it's false. Even "f(x) = x^3 + 2x" is not a polynomial. That would be a polynomial function.
To be a polynomial, an expression has to have integer exponents >= 0 (the constant term would be cx^0).
So x^3 + 2x^1/3 is not a polynomial.
So it's a function, but not a polynomial function.
Also, your reasoning is incorrect.
x^4 + 7x is a polynomial and a binomial. An expression can be both a polynomial and a binomial.
g(x) = x^4 + 7x is a polynomial function.
- llafferLv 75 months ago
If you mean:
f(x) = x³ + 2x^(1/3)
Then it isn't a polynomial because the exponent isn't an integer.
If it was:
f(x) = x³ + (2/3)x
Then yes, that would be considered a polynomial.
- PuzzlingLv 75 months ago
You need parentheses if you want ⅓ to be the exponent. As written you have:
f(x) = x^3 + 2x^1/3
= x^3 + 2x/3
= x^3 + (2/3)x
Anyway, I believe you meant:
f(x) = x^3 + 2x^(1/3)
The issue is not the number of terms (a binomial or even a monomial is still a polynomial).
The reason it is not a polynomial is that all of the terms must have a whole number exponent (non-negative integer).
Because the exponent is a fraction (1/3), this is not a polynomial.
Answer:
False
Read more about polynomials at the link below.