algebra II question that i don’t even know how to type so here’s a photo?

I think that is:

∛(x⁵) / (x²)^(2/3) = xᵃ

The first thing I'll do is turn the cube root into a fraction exponent.  Since it's a cube root the denominator is 3:

x^(5/3) / (x²)^(2/3) = xᵃ

Next, I'll look at the denominator.  The exponent of an exponent is the same as the product of exponents.  This gives us:

x^(5/3) / x^(2 * 2/3) = xᵃ

x^(5/3) / x^(4/3) = xᵃ

Now we have the quotient of two numbers with the same base.  This can be simplified by getting the difference of the two exponents:

x^(5/3 - 4/3) = xᵃ

x^(1/3) = xᵃ

Finally, we have two values that are the same with the same bases so the exponents must be equal:

a = 1/3