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Physics Circular Motion?
What is the centripetal acceleration of the Earth in its orbit around the sun? Assume that the Earth orbits in a circle with a radius of 1.5 x 10^11 m
2 Answers
- SlowfingerLv 64 months agoFavorite Answer
centripetal acceleration
a = v² / r = r ω ²
Angular velocity
ω = 2π/T
where T is a period for one circle
For Earth
T = 365.25 days = 365.25 * 86400s = 3.156×10⁷ s
ω = 2π / 3.156×10⁷ = 1.991×10⁻⁷ rad/s
a = 1.5×10¹¹ * (1.991×10⁻⁷)² = 5.95×10⁻³ m/s²
- az_lenderLv 74 months ago
a = v^2/r = (2pi*r/T)^2/r
= 4*pi^2*r/(1 year)^2
= 4*pi^2*(1.5 x 10^11 m)/(86400 s)^2
= 793 m/s^2.
