Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
Algebra 2 Word Problem?
The speed of a vehicle just before the brakes are applied can be estimated by using the formula
𝑠 = (28.75𝑑)^1⁄2, where s is the speed (in miles per hour) of the vehicle and d is the length (in feet) of the skid marks the vehicle leaves. How fast was a car traveling if it left skid marks 45 feet long? Round your answer to the nearest hundredth.
2 Answers
- llafferLv 72 months ago
You are given the equation:
s = (28.75d)^(1/2)
Where "s" is the speed in miles per hour and "d" is the length of the skid mark in feet.
You are then given the length of a known skid mark (45 ft) and asked to estimate the speed. Substitute and simplify.
The 1/2 exponent is the same as a square root so:
s = √(28.75d)
Substitute and simplify:
s = √(28.75 * 45)
s = √1293.75
s = 35.97 miles per hour (rounded to 2DP)
