Two equally charged particles, held 3.6 × 10^-3 m apart, are released from rest.?

Question

Two equally charged particles, held 3.6 × 10^-3 m apart, are released from rest. The initial acceleration of the first particle is observed to be 5.4 m/s^2 and that of the second to be 10 m/s^2. If the mass of the first particle is 8.6 × 10^-7 kg, what are (a) the mass of the second particle and (b) the magnitude of the charge of each particle?
PLEASE CLEAR ANSWERS WITH UNITS THANKS

billrussell42 · Answer

here is a very similar Q/A, that you asked earlier. Just change the numbers and recalculate.

let q be the charge
m₁ and m₂ the masses
F on both = kq²/r² = q²(9e9)/(2.8e-3)² = q²1.148e15

F = m₁a₁
F = m₂a₂

q²1.148e15 = m₁9.3
q²1.148e15 = m₂11 = 11•4.8e-7

q² = 11•4.8e-7 / 1.148e15 = 4.60e-21
q = 6.78e-11 C or 678 nC

m₁ = q²1.148e15 / 9.3 = 4.60e-21(1.148e15) / 9.3
    = 5.68e-7 kg or 56.8 mg

Coulomb's law, force of attraction/repulsion
F = kQ₁Q₂/r²
   Q₁ and Q₂ are the charges in coulombs
   F is force in newtons
   r is separation in meters
   k = 8.99e9 Nm²/C²

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Two equally charged particles, held 3.6 × 10^-3 m apart, are released from rest.?

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