Write the equation of the line with a slope of -5/3 passing through the point (-2,4) in slope intercept form or point slope?

Point-slope form is:

y - y₁ = m(x - x₁)

You are given the point (-2, 4) and the slope -5/3, so you just substitute in the values to get:

y - 3 = (-5/3)(x + 2)

To get this in slope-intercept form, simplify the right side and then solve for y:

y - 3 = (-5/3)x - 10/3

y = (-5/3)x - 10/3 + 9/3

y = (-5/3)x - 1/3

y = mx + b

1st we solve for the y - intercept b from the slope intercept form formula.

4 = - 5/3(-2) + b

4 = 10/3 + b

4 - 10/3 = b

b = 2/3

Therefore the equation of the line is y = - 5/3x + 2/3 ...