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Can You Solve This Math Problem?
X^3 + Y^3 + Z^3 = K for all values of K from 1 to 100??
There is something special about K=42
So can you find the Values of X, Y, Z when K = 42
4 Answers
- Ian HLv 72 months agoFavorite Answer
No solutions for positive integers only, cubes adding to 42.
If negative integers allowed and we relax the 100 limit then ...
(80435758145817515)^3 + (-80538738812075974)^3 + (12602123297335631)^3 = 42.
- Jeffrey KLv 72 months ago
If X,Y,Z can be any real numbers, there are an infinite number of solutions. If they must be positive integers, there are no solutions for a K of 42.
- ?Lv 72 months ago
Sure. X = Y = Z = cube root of 14.
If you want integer solutions, you'd have to make one or two of the X, Y, Z negative, and I'm not sure that would produce a solution.
