1. Study the circuit shown and answer the following questions (the capacitor is completely discharged at t=0)   'R=0.8 M OHM' 'C=5uF'?

b) zero

c) battery voltage v₀ (not stated)

d) v = v₀[1–e^(–t/τ)] = v₀[1–e^(–1)]

v = 0.63v₀

Q = CV = 0.63v₀(5µ) = v₀(3.15) µC

e) Q = CV = v₀(5µ) = v₀(5) µC

voltage on a cap, charging

v = v₀[1–e^(–t/τ)]

v₀ is the battery voltage

v is the voltage after time t

R is resistance in ohms,

C is capacitance in farads

t is time in seconds

RC = τ = time constant

After 1τ, v = 0.63v₀

After 2τ, v = 0.86v₀

After 3τ, v = 0.95v₀

After 5τ, v = 0.993v₀